Integrand size = 13, antiderivative size = 46 \[ \int (a+b x)^m (c+d x) \, dx=\frac {(b c-a d) (a+b x)^{1+m}}{b^2 (1+m)}+\frac {d (a+b x)^{2+m}}{b^2 (2+m)} \]
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Time = 0.01 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {45} \[ \int (a+b x)^m (c+d x) \, dx=\frac {(b c-a d) (a+b x)^{m+1}}{b^2 (m+1)}+\frac {d (a+b x)^{m+2}}{b^2 (m+2)} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(b c-a d) (a+b x)^m}{b}+\frac {d (a+b x)^{1+m}}{b}\right ) \, dx \\ & = \frac {(b c-a d) (a+b x)^{1+m}}{b^2 (1+m)}+\frac {d (a+b x)^{2+m}}{b^2 (2+m)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.89 \[ \int (a+b x)^m (c+d x) \, dx=\frac {(a+b x)^{1+m} (-a d+b c (2+m)+b d (1+m) x)}{b^2 (1+m) (2+m)} \]
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Time = 0.38 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.07
method | result | size |
gosper | \(-\frac {\left (b x +a \right )^{1+m} \left (-b d m x -b c m -b d x +a d -2 b c \right )}{b^{2} \left (m^{2}+3 m +2\right )}\) | \(49\) |
risch | \(-\frac {\left (-d \,x^{2} b^{2} m -a b d m x -b^{2} c m x -d \,x^{2} b^{2}-a b c m -2 b^{2} c x +a^{2} d -2 a b c \right ) \left (b x +a \right )^{m}}{b^{2} \left (2+m \right ) \left (1+m \right )}\) | \(81\) |
norman | \(\frac {d \,x^{2} {\mathrm e}^{m \ln \left (b x +a \right )}}{2+m}+\frac {\left (a d m +b c m +2 b c \right ) x \,{\mathrm e}^{m \ln \left (b x +a \right )}}{b \left (m^{2}+3 m +2\right )}-\frac {a \left (-b c m +a d -2 b c \right ) {\mathrm e}^{m \ln \left (b x +a \right )}}{b^{2} \left (m^{2}+3 m +2\right )}\) | \(96\) |
parallelrisch | \(\frac {x^{2} \left (b x +a \right )^{m} a \,b^{2} d m +x^{2} \left (b x +a \right )^{m} a \,b^{2} d +x \left (b x +a \right )^{m} a^{2} b d m +x \left (b x +a \right )^{m} a \,b^{2} c m +2 x \left (b x +a \right )^{m} a \,b^{2} c +\left (b x +a \right )^{m} a^{2} b c m -\left (b x +a \right )^{m} a^{3} d +2 \left (b x +a \right )^{m} a^{2} b c}{\left (2+m \right ) a \left (1+m \right ) b^{2}}\) | \(138\) |
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none
Time = 0.23 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.80 \[ \int (a+b x)^m (c+d x) \, dx=\frac {{\left (a b c m + 2 \, a b c - a^{2} d + {\left (b^{2} d m + b^{2} d\right )} x^{2} + {\left (2 \, b^{2} c + {\left (b^{2} c + a b d\right )} m\right )} x\right )} {\left (b x + a\right )}^{m}}{b^{2} m^{2} + 3 \, b^{2} m + 2 \, b^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 377 vs. \(2 (37) = 74\).
Time = 0.34 (sec) , antiderivative size = 377, normalized size of antiderivative = 8.20 \[ \int (a+b x)^m (c+d x) \, dx=\begin {cases} a^{m} \left (c x + \frac {d x^{2}}{2}\right ) & \text {for}\: b = 0 \\\frac {a d \log {\left (\frac {a}{b} + x \right )}}{a b^{2} + b^{3} x} + \frac {a d}{a b^{2} + b^{3} x} - \frac {b c}{a b^{2} + b^{3} x} + \frac {b d x \log {\left (\frac {a}{b} + x \right )}}{a b^{2} + b^{3} x} & \text {for}\: m = -2 \\- \frac {a d \log {\left (\frac {a}{b} + x \right )}}{b^{2}} + \frac {c \log {\left (\frac {a}{b} + x \right )}}{b} + \frac {d x}{b} & \text {for}\: m = -1 \\- \frac {a^{2} d \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} + \frac {a b c m \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} + \frac {2 a b c \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} + \frac {a b d m x \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} + \frac {b^{2} c m x \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} + \frac {2 b^{2} c x \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} + \frac {b^{2} d m x^{2} \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} + \frac {b^{2} d x^{2} \left (a + b x\right )^{m}}{b^{2} m^{2} + 3 b^{2} m + 2 b^{2}} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.37 \[ \int (a+b x)^m (c+d x) \, dx=\frac {{\left (b^{2} {\left (m + 1\right )} x^{2} + a b m x - a^{2}\right )} {\left (b x + a\right )}^{m} d}{{\left (m^{2} + 3 \, m + 2\right )} b^{2}} + \frac {{\left (b x + a\right )}^{m + 1} c}{b {\left (m + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 132 vs. \(2 (46) = 92\).
Time = 0.28 (sec) , antiderivative size = 132, normalized size of antiderivative = 2.87 \[ \int (a+b x)^m (c+d x) \, dx=\frac {{\left (b x + a\right )}^{m} b^{2} d m x^{2} + {\left (b x + a\right )}^{m} b^{2} c m x + {\left (b x + a\right )}^{m} a b d m x + {\left (b x + a\right )}^{m} b^{2} d x^{2} + {\left (b x + a\right )}^{m} a b c m + 2 \, {\left (b x + a\right )}^{m} b^{2} c x + 2 \, {\left (b x + a\right )}^{m} a b c - {\left (b x + a\right )}^{m} a^{2} d}{b^{2} m^{2} + 3 \, b^{2} m + 2 \, b^{2}} \]
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Time = 0.46 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.91 \[ \int (a+b x)^m (c+d x) \, dx={\left (a+b\,x\right )}^m\,\left (\frac {a\,\left (2\,b\,c-a\,d+b\,c\,m\right )}{b^2\,\left (m^2+3\,m+2\right )}+\frac {x\,\left (2\,b^2\,c+b^2\,c\,m+a\,b\,d\,m\right )}{b^2\,\left (m^2+3\,m+2\right )}+\frac {d\,x^2\,\left (m+1\right )}{m^2+3\,m+2}\right ) \]
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